Syllabus: Introduction: In differentiation, if a function is given, then we know how to find its derivative. Let us take up the reverse problem. i.e, if the derivative of a function is given, we can find the function. This is to find a function whose derivative is given as a function f(x). A function F(x) […]
INTEGRAL CALCULUS – I (UNIT – 4 FOR NON – CIRCUIT AND UNIT – 5 FOR CIRCUIT) Read More »
Aim: Data Set: Im = 40, ω = 10, L = 1 Procedure: Output: Output for fixed t and various values of ω ω i(t) v(t) 1 19.18 35.1 2 33.66 43.22 3 39.9 8.49 4 36.37 -66.58 5 23.94 -160.23 6 5.64 -237.6 Output for fixed ω and various values of t t i(t)
Aim: Procedure: To evaluate the power factor. Output: Output for phasor diagram of the system Description Value / Expression Phasor sum S=550+952.63i Phasor angle α = 600 Power factor a = 0.5 Apparent power 1100 Active power 550 Reactive power 952.63 Output for power factor Description Value / Expression Active power (P) 10 Power factor
Ex-6 – COMPLEX NUMBERS – PHASOR SUM – POWER FACTOR Read More »
Aim: Given complex number : z1 = 4 + 3i Procedure: Output: Output for Real Part, Imaginary Part, Conjugate, Modulus and Argument Complex number z1=4+3i Real part R=4 Distance of z1 from y axis 4 Is real part of z1 and the distance of z1 from y axis is equal? Yes Imaginary part I=3 Distance
Aim: Data Set: Im = 110, ω = 90, R = 5 Procedure: Output: Output for current and voltage Description Value Maximum value of current (I_m) 110 Angular velocity (ω) 90 Resistance (R) 5 Maximum value of voltage (V_m) 550 Root mean square current(I_rms) 77.78 Frequency (F) 141.37 Output for instantaneous current for various time
Aim: Procedure Output: Output table for y = 5 sin (3x + 2) and y = 4 cos (2x – 1) Function y = 5 sin (3x + 2) y = 4 cos (2x – 1) Domain -∞ <= x <= ∞ -∞ <= x <= ∞ Range -5 <= y <= 5 -5 <=
Ex – 2 Procedure Output: Output table for parabolic shaped satellite dish antenna Equation of the Parabola \[x^2\ -\ 4.2\ x\ -\ 4.8\ y\ =\ -\ 15.45\] Vertex (V) (2.1, 2.3) Focus (F) (2.1, 3.5) Equation of the Directrix y = 1.1 Length of latus rectum 4.8 Distance of the receiver from vertex (V) 1.2
Aim: Procedure Output: Output for parabolas Equation of the Parabola \[(y-k)^2\ =\ 4\ a\ (x\ -\ h)\] \[(x-h)^2\ =\ 4\ a\ (y\ -\ h)\] Vertex (5,2) (5,2) Focus (7,2) (5,4) Distance from vertex to focus 2 2 Axis y = 2 x = 5 Directrix x = 3 y = 0 Latus rectum x =
DR.B.R.AMBEDKAR POLYTECHNIC COLLEGE – YANAM BASIC ENGINEERING BOARD PRACTICAL EXAMINATION – APRIL 2024 Scheme: R 2023 APPLIED MATHEMATICS – II Marks: 100 Time :
Syllabus: General equation of conics – Classification of conics – Standard equations of parabola – Vertex, focus, axis, directrix, focal distance, focal chord, latus-rectum of parabola , Standard equations of ellipse – Vertices, foci, major axis, minor axis, directrices, eccentricity, centre and latus-rectums of ellipse – Simple problems. Conic: A conic is defined as the locus of a point which moves such that its distance from
COORDINATE GEOMETRY (UNIT – 1 FOR CIRCUIT AND UNIT – 2 FOR NON – CIRCUIT) Read More »
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