## N – 2.2 – Product of two vectors – Exercise Problems with solutions

Part – A Soln: = 1(1) + 1(1) + 0 = 1 + 1 = 2 Soln: = 2(3) + 3(2) – 2 (6) = 6 + 6 -12 = 0 Soln: 2(p) + 1(3) – 5 (-2) = 0 2p + 3 +10 = 0 2p + 13 = 0 Soln: Part –B Soln: Soln: Part –C Soln: = 1(1) + 2(1) + 1(-3) = 0 = 1(7) + 1(-4) – 3(1) = 7 – 4 – 3 = 0 = 7(1) -4 (2) + 1 (1) = 7…

## N – 2.2 – Product of two vectors – Exercise Problems

Part – A Part –B Part –C

## N – 2.1 – Vector Introduction – Exercise Problems with Solutions

Part – A Soln: Given Sol.:     Given Soln: Part –B 1. Show that the points whose position vectors Soln:   Given Part –C Prove that the points Soln: Given The given triangle is an equilateral triangle. 2. Prove that the points whose position  vectors  are Soln: Given The given triangle is an right angled triangle.

## 2.1 – N – Vector Introduction – Exercise Problems

Part – A Part –B 1. Show that the points whose position vectors Part –C Prove that the points 2. Prove that the points whose position  vectors  are

## 2.3 APPLICATION OF SCALAR AND VECTOR PRODUCT

Application of Scalar Product Work done PART – B Example  : Soln: = 3 ( 2 ) + 5 ( – 1 ) + 7 ( 1 ) =    6  – 5  +  7 Work done = 8 units Example  : Soln: = 4 ( 2 ) + 9 ( – 7 ) + 4 ( 1 ) =    8  – 63  +  4     Work done  =  –51 units Work done  =  51 units  (by taking positive value) Example  : is displaced from the point ( 1, 1,  1…