1.3 – N – CONICS – Exercise Problems with solutions

Part – A Prove that the equation  x2  –  2xy  + y2 – 16x – 12y + 22 = 0 is a parabola.  Soln:    x2  –  2xy  + y2 – 16x – 12y + 22 = 0                    —————–   ( 1 ) Condition for  ( 1 ) to represent parabola is  h2 = ab From ( 1 )   a =  1,    b = 1 2h = -2  ⇒  h = -1 h2 = ab (-1)2  =   1 ( 1) 1 = 1 1 = 1.                 ∴  ( 1 )   represents a…

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