## N-SCHEME-ENGINEERING MATHEMATICS-II MODEL EXAM QUESTION PAPER/2021

MODEL EXAM QUESTION PAPER 40022 ENGINEERING MATHEMATICS – II Time : 3.00 Hours                       Date:  22-05-2021                                              Max.Marks: 100 Note: 1. Answer all question in PART A. Each question carries one mark. 2. Answer any ten questions in PART B. Each question carries two marks. 3. Answer all question by selecting either A or B. Each question carries fifteen marks. 4. Clarkes Table and programmable calculators are not permitted.                                                PART – A                                                 (5×1=5)                                                                                                                                                     1.         Find the value of  ‘p’if the pair of  lines px2-5xy  + 7y2 =  0 …

## N – 2.2 – Product of two vectors – Exercise Problems with solutions

Part – A Soln: = 1(1) + 1(1) + 0 = 1 + 1 = 2 Soln: = 2(3) + 3(2) – 2 (6) = 6 + 6 -12 = 0 Soln: 2(p) + 1(3) – 5 (-2) = 0 2p + 3 +10 = 0 2p + 13 = 0 Soln: Part –B Soln: Soln: Part –C Soln: = 1(1) + 2(1) + 1(-3) = 0 = 1(7) + 1(-4) – 3(1) = 7 – 4 – 3 = 0 = 7(1) -4 (2) + 1 (1) = 7…

## N – 2.2 – Product of two vectors – Exercise Problems

Part – A Part –B Part –C

## N – 2.1 – Vector Introduction – Exercise Problems with Solutions

Part – A Soln: Given Sol.:     Given Soln: Part –B 1. Show that the points whose position vectors Soln:   Given Part –C Prove that the points Soln: Given The given triangle is an equilateral triangle. 2. Prove that the points whose position  vectors  are Soln: Given The given triangle is an right angled triangle.

## 2.1 – N – Vector Introduction – Exercise Problems

Part – A Part –B 1. Show that the points whose position vectors Part –C Prove that the points 2. Prove that the points whose position  vectors  are

## 1.3 – N – CONICS – Exercise Problems with solutions

Part – A Prove that the equation  x2  –  2xy  + y2 – 16x – 12y + 22 = 0 is a parabola.  Soln:    x2  –  2xy  + y2 – 16x – 12y + 22 = 0                    —————–   ( 1 ) Condition for  ( 1 ) to represent parabola is  h2 = ab From ( 1 )   a =  1,    b = 1 2h = -2  ⇒  h = -1 h2 = ab (-1)2  =   1 ( 1) 1 = 1 1 = 1.                 ∴  ( 1 )   represents a…

## 1.3 – N – CONICS Exercise Problems

Part – A Prove that the equation  x2  –  2xy  + y2 – 16x – 12y + 22 = 0 is a parabola.  2. Show that the equation  7×2  +  3xy  + 2y2 – x + 2y – 1 = 0  represents an ellipse. Part – C Find axis, vertex, focus and equation of directrix for y2 + 4x + 6y + 17 = 0.

## 1.2 – N – Analytical Geometry Exercise Problems With Solutions

Part – A 1.  Find the equation of the circle with centre (1, -2) and radius 5 units. Soln:   We know that  the  equation of circle is (x – h )2 + (y – k )2    =   r2 Here h =  1,  k = – 2  (given)   and   r  =  5 (x – 1 )2  + (y + 2 )2 = 52 x2 – 2x + 1+  y2 +  4y + 4= 25 x2  +   y2   – 2x  + 4y + 5 -25 = 0 x2  +   y2    –…

## 1.2 – N – Analytical Geometry – II Exercise Problems

Part – A 1.  Find the equation of the circle with centre (1, -2) and radius 5 units. 2.     Find the centre and radius of the circle  x2  +   y2 +  10x  +  8y  +  5 = 0 . 3.     Find the equation of the circle passing through the point (1 , 1 ) and concentric to the circle x2  +   y2  +  4x  +  6y  –  15 = 0.  Part – B 1.    Find the equation of the circle passing through the point  A (2, 3) and having its centre at…

## 1.1 – N – Analytical Geometry Exercise Problems With Solutions

Part – A 1.  Find the perpendicular distance from the point (3, -5) to the straight line 3x-4y-26=0. Soln: W.K.T  The length of the perpendicular distance from (x1,y1) to the line ax + by + c = 0  is ±  (ax1 + by1 + c)/ √(a2 + b2 ) Given straight line is     3x-4y-26 =0 Given point (x1,y1)  =  (3, -5) i.e  ±  3(3) – 4(-5) – 26/ √(32 + (-4)2 )   =   3 / 5 2.     Find the distance between the line 3x+4y = 9 and 6x+8y = 15. Soln: W.K.T …

## 1.1 – N – Analytical Geometry Exercise Problems

Part – A 1.  Find the perpendicular distance from the point (3, -5) to the straight line 3x-4y-26=0. 2.     Find the distance between the line 3x+4y = 9 and 6x+ 8y = 15. 3.     Show that the lines 3x+2y+9=0 and 12x+8y-15 =0 are parallel. 4.     Find ‘p’ such that the lines 3x+4y = 8 and px + 2y = 7 are parallel. 5.    Show that the lines 27x-18y+25 =0 and 2x + 3y+7 =0 are perpendicular. 6.    Find the value of k if the lines 2x + ky -11 =0  and  5x…

## Diploma Continuous Assessment Test -2/ April – 2021

Course: First year Diploma course in Engineering & Technology Subject & Code : Engineering Mathematics – II (40022) Time : 2 Hours                   Date:  27-04-2021                                              Max. Marks: 50 PART – A  Answer all questions                                          ( 6×1=6 marks) Soln: =    1  ( 1 – 0 )  – 1 ( 0 – 1 )  + 0 (  0 – 1 ) =   1 ( 1 )  -1 (- 1 ) +  0 =   1 + 1 =   2 2.            Define vector Differential operator. Soln: Soln: =   yz  + 3×2 ( 1 ) …

## DEFINITE INTEGRALS

Definition of Definite Integrals: Example  : Soln: Example  : Soln: Example  : Soln: Example  : Soln: Example  : Soln: Example  : Soln: Example  : Soln: Example  : Soln: Example  : Soln: du  = cos x dx Example  : Soln: Adding ( 1 ) &  ( 2 )

## BERNOULLLI’S FORMULA

If u and v are functions x, then Bernoulli’s form of integration by parts formula is Where u΄, u΄΄,u΄΄΄….. are successive differentiation of the function u and v, v1, v2, v3, …………. the successive integration of the function dv. Note: The function ‘u’ is differentiated up to constant. Example  : Soln: ILATE Example  : Soln: Example  : Soln: ILATE Example  : Soln: ILATE Example  : Soln: ILATE

## 5.1 INTEGRATION BY PARTS

Introduction: When the integrand is a product of two functions and the method of decomposition or substitution can not be applied, then the method of by parts is used. Integraiton by parts formula: The above formula is used by taking proper choice of ‘u’ and ‘dv’. ‘u’ should be chosen based on thefollowing order of Preference. Simply remember ILATE 1. Inverse trigonometric functions: 2. Logarithmic functions: log x 3. Algebraic functions: 4. Trigonometric functions: sin x, cos x, tan x, etc. 5. Exponential functions: Example:  Soln: ILATE u = x                                    …

## 4.3 STANDARD INTEGRALS

List of  Formulae: Example : Soln: Example : Soln: Example : Soln: Example : Soln: Put      u  = 3x + 2 Example : Soln: Example : Soln: Put      u  = 3x – 2 Example : Soln: Example : Soln: Amazon.in Widgets Example : Soln: Example : Soln:

## 4.2 INTEGRATION BY SUBSTITUTION

So far we have dealt with functions, either directly integrable using integration formula (or) integrable after decomposing the given functions into sums & differences. which cannot be decomposed into sums (or) differences of simple functions. In these cases, using proper substitution, we shall reduce the given form into standard form, which can be integrated using basic integration formula. When the integrand (the function to be integrated) is either in multiplication or in division form and if the derivative of one full or meaningful part of the function is equal to…

## 4.1 INTEGRATION – DECOMPOSITION METHOD

Sir Sardar Vallabhai Patel, called the Iron Man of India integrated several princely states together while forming our country Indian Nation after independence. Like that in Maths while finding area under a curve through integration, the area under the curve is divided into smaller rectangles and then integrating (i.e) summing of all the area of rectangles together. So, integration means of summation of very minute things of the same kind. Integration as the reverse of differentiation:             Integration can also be introduced in another way, called integration as the reverse…

## APPLICATION OF VECTOR DIFFERENTIATION

is a vector function, defined and differentiable at each point (x, y, z)in a certain region of space [i.e., A defines a vector field], then the divergence of  (abbreviated as ‘Div ‘) is defined as,  Basic properties of Divergence: If A, B are vector functions and ‘f’ is a scalar function, then Example: Soln: =   yz  + 3×2 ( 1 )  + ( 0 – y3 ) =  yz  + 3×2 – y3 Example: Soln: At ( 1, -1, 2) =    -2  – 4  – 1 =   -7 Example: Soln:…

## VECTOR DIFFERENTIATION

Vector point function and Vector field: Let P be any point in a region ‘D’ of space.  Let r be the position vector of P.  If there exists a vector function F corresponding to each P,  then such a function F is called a vector function and the region D is called a vector field. Example:  consider the vector function Let P be a point whose position vector is At P , the value of F is obtained by putting x = 2, Y = I, z = 3 in…

## 3.1 PRODUCT OF THREE AND FOUR VECTORS

Scalar triple Product Properties of Scalar triple Product: Example  : Soln: =    1  ( 1 – 0 )  – 1 ( 0 – 1 )  + 0 (  0 – 1 ) =   1 ( 1 )  -1 (- 1 ) +  0 =   1 + 1 =   2 Example  : Soln: =    2  ( 4 + 2 )  – 1 (3 – 1 )  + 1 ( -6 – 4 ) =   2 ( 6 )  – 1 (2 ) +  1 ( – 10 ) =   12 –…

## 2.3 APPLICATION OF SCALAR AND VECTOR PRODUCT

Application of Scalar Product Work done PART – B Example  : Soln: = 3 ( 2 ) + 5 ( – 1 ) + 7 ( 1 ) =    6  – 5  +  7 Work done = 8 units Example  : Soln: = 4 ( 2 ) + 9 ( – 7 ) + 4 ( 1 ) =    8  – 63  +  4     Work done  =  –51 units Work done  =  51 units  (by taking positive value) Example  : is displaced from the point ( 1, 1,  1…

## 2.2 PRODUCT OF VECTORS

Definition:  Properties of Scalar Product: Example  : Soln: = 2(3) – 4 (-6) + 8 (12) = 6 + 24 + 96 = 126 Example  : Soln: = 2(3) + 3(2) – 2 (6) = 6 + 6 -12 = 0 Soln: 3(-6) – 1(m) + 5 (4) = 0 -18 – m + 20 = 0 -m + 2 = 0 m = 2 Soln: = 1(0) – 1(4) + 2 (2) = 0 = 0(-10) + 4(-2) + 2 = 0 – 8 + 8 = 0 =…

## 2.1 VECTOR – INTRODUCTION

Vectors constitute one of the several Mathematical systems which can be usefully employed to provide mathematical handling for certain types of problems in Geometry, Mechanics and other branches of Applied Mathematics. Vectors facilitate mathematical study of such physical quantities as possess Direction in addition to Magnitude. Velocity of a particle, for example, is one such quantity. Physical quantities are broadly divided in two categories viz (a) Vector Quantities & (b) Scalar quantities. ( a ) Vector quantities : Any quantity, such as velocity, momentum, or force, that has both magnitude…

## 1.3 CONICS

Conic: A conic is defined as the locus of a point which moves such that its distance from a fixed point is always ‘e’ times its distance from a fixed straight line. Focus: The fixed point is called the focus of the conic. Directrix: The fixed straight line is called the directrix of the conic. Eccentricity: The constant ratio is called the eccentricity of the conic. General equation of a conic  ax2  +  2hxy  + by2 + 2gx + 2fy + c = 0  represents (i) a circle if a…

## 1.2 ANALYTICAL GEOMETRY II

EQUATION OF CIRCLE Definition:         A circle is the locus of a point which moves in a plane in such a way that its distance from a fixed point remains constant.   The fixed point is called the centre of the circle and the constant distance is called the radius of the circle. Equation of the circle with centre (h, k)  and radius ‘r’ units. CP = r                                                                                                                            √(( x – h )2 + (y – k )2   =  r (Using distance formula)  (x – h )2 + (y – k )2…